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First solution in Clear category for Feed Pigeons by danielmp
def checkio(number):
#minute
mn = 1
while True:
if number < mn*(mn+1)//2:
break
number -= mn*(mn+1)//2
mn += 1
#max between the amount of pidgeons in the previous (minute)iteration and the rest of number
return max(mn*(mn-1)//2, number)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(1) == 1, "1st example"
assert checkio(2) == 1, "2nd example"
assert checkio(5) == 3, "3rd example"
assert checkio(10) == 6, "4th example"
Dec. 28, 2014
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