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First solution in Clear category for Even the Last by Rafal.U
def checkio(array):
"""
sums even-indexes elements and multiply at the last
"""
n = len(array)
licznik = 0
wynik = 0
x = 0
if n > 0:
for i in array:
if licznik % 2 == 0: #sumowanie parzystych elementow
x = wynik + array[licznik]
wynik = x
licznik += 1 #zwiekszanie indeksu listy
wynik = x*array[licznik-1] #mnozenie parzystej sumy przez ostatni element
return wynik
if n == 0:
return 0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([0, 1, 2, 3, 4, 5]) == 30, "(0+2+4)*5=30"
assert checkio([1, 3, 5]) == 30, "(1+5)*5=30"
assert checkio([6]) == 36, "(6)*6=36"
assert checkio([]) == 0, "An empty array = 0"
Oct. 29, 2016