5 strings clear solution for Even the Last by Alexey_Dronov - python coding challenges

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5 strings solution in Clear category for Even the Last by Alexey_Dronov

def checkio(array: list) -> int:
    if len(array) == 0:
        return 0
    a = array[::2]
    mult = sum(a) * array[(len(array) - 1)]
    return mult

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    print('Example:')
    print(checkio([0, 1, 2, 3, 4, 5]))
    
    assert checkio([0, 1, 2, 3, 4, 5]) == 30, "(0+2+4)*5=30"
    assert checkio([1, 3, 5]) == 30, "(1+5)*5=30"
    assert checkio([6]) == 36, "(6)*6=36"
    assert checkio([]) == 0, "An empty array = 0"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

April 8, 2020

Comments:

kaiogu on June 4, 2020, 5:59 a.m.
<p>Well done, there are just some parts that could be improved: 1. To access the last element of an array you can just do `array[-1]`</p> <ol> <li>I was once told that it is not good to have two exit points to a function (two `return` statements). The solution here would be to assign to `result` in both cases and return this `result`.</li> </ol> <p>Other than that you could condense the function, like instead of assingning to a variable in line 4, just use that in the expression on the line below. Same with assigning to mult on line 5, just return the result of the expression.</p>

List but not the least

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