DahliaSR Pythonified clear solution for The End of Other by veky - python coding challenges

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DahliaSR Pythonified solution in Clear category for The End of Other by veky

from itertools import permutations as perm
checkio = lambda words: any(one.endswith(other) for one, other in perm(words, 2))

Aug. 20, 2017

Comments:

alabama_09 on April 19, 2019, 3:05 p.m.
Nice! Using 'any' function is a very elegant solution for this mission and also comfortable to read the whoke code.

veky on Nov. 10, 2020, 6:50 a.m.
Yes, "any(one" reads nicely. :-D

2010min0ru on Nov. 8, 2020, 2:34 p.m.
Permutations with second argument is exactly what i was looking instead of itertools.combinations >_<.

veky on Nov. 10, 2020, 6:49 a.m.
I find it very curious that someone would know about combinations without knowing about permutations. :-) Or do you mean you thought about only "total" permutations (of all elements) until now?

2010min0ru on Nov. 10, 2020, 11:14 a.m.
I guess that i never used "r" argument with itertools.permutations before. Yep seems like I am only used permutations of the all elements.

veky on Nov. 10, 2020, 3:52 p.m.
Yeah, that's "old school" (depicted here: <a href="http://users.telenet.be/vdmoortel/dirk/Maths/PermVarComb.html).">http://users.telenet.be/vdmoortel/dirk/Maths/PermVarComb.html).</a> "New school" is simpler and more symmetric: <a href="https://www.mathsisfun.com/combinatorics/combinations-permutations.html.">https://www.mathsisfun.com/combinatorics/combinations-permutations.html.</a>

2010min0ru on Nov. 10, 2020, 4:01 p.m.
Thank you for combinatorics lesson :) Maybe now i would not brute force itertools every time to sort out which of combinatoric function to use xD

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