lazy generator one line solution clear solution for The End of Other by roenke - python coding challenges

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lazy generator one line solution solution in Clear category for The End of Other by roenke

def checkio(words_set):
    return any(word for word in words_set 
               for w in words_set 
               if word != w and word.endswith(w))

June 3, 2016

Comments:

iiojj2 on June 6, 2016, 11:45 p.m.
<p>cool</p>

2010min0ru on Nov. 8, 2020, 2:43 p.m.
<p>Didn't realized that any() would interrupt iteration over generator. That is useful trick to know! Thank you.</p>

Different kind of sets

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