First clear solution for The End of Other by panaro32 - python coding challenges

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First solution in Clear category for The End of Other by panaro32

def checkio(s):
    return any(map(lambda x: any(map(x.endswith,s-set([x]))),s))

May 12, 2014

Comments:

nickie on May 12, 2014, 9:18 p.m.
The challenge is <a href="http://www.checkio.org/mission/end-of-other/publications/nickie/python-3/set-permutations/#comment-outer-9549">here</a>...

johndrunner on May 15, 2014, 12:23 p.m.
I learned a lot from this one after spending time sifting through doc.python.org. Thank you for sharing it. However, you should provide comments explaining how this code works since it has been posted in the clear section. At first glance, I had no idea how this worked.

Akay on June 22, 2014, 9:16 a.m.
Nice solution. I forgot about lambda function

panaro32 on June 22, 2014, 7:57 p.m.
Thanks! :)

xtofl on Aug. 1, 2014, 5:23 p.m.
Great functional style! You could write `set([x])` as `{x}`.

panaro32 on Aug. 1, 2014, 10:40 p.m.
You're right! Thanks!

FarhadIsmailov on Oct. 5, 2014, 7:02 p.m.
But as I understand the solution complexity is still remains O(n^2)

maurice.makaay on Nov. 3, 2014, 5:52 p.m.
-1 for posting this under Clear.

Hayertjez on Nov. 18, 2015, 1:21 p.m.
Yes, this is not clear.

marshall.zheng on Dec. 25, 2014, 7:27 a.m.
extremely good

mauricioabreu on April 22, 2015, 3:43 a.m.
It is a good solution but it is not clear. And it is not clear just because it has lambda, any, map, etc. It is a one line solution that does a lot of stuff. :-) Good solution though! +1

panaro32 on April 23, 2015, 10:07 p.m.
You are right. I regret some of the 'clear' vs 'creative' decisions I made. Thank you for your input! :-)

totee19 on Oct. 24, 2015, 2:29 p.m.
Too many imbrications. I can't understand easy when I read your code I think it's for creative section as you said in your last comment. Plz don't angry to me. It's just my opinion. :)

M157q on Nov. 5, 2015, 1:53 p.m.
same as mine!

viktor.chyrkin on Oct. 27, 2021, 12:18 p.m.
put this in creative.

CDG.Axel on Feb. 12, 2022, 1:19 p.m.
Great! But map(lambda) always longer than simple comprehension: <pre class='brush: python'>return any(map(lambda x: any(map(x.endswith, s - {x})), s)) vs return any(any(map(x.endswith, s - {x})) for x in s) vs return any(a.endswith(b) for a in s for b in s - {a}) </pre>

Different kind of sets

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