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First solution in Clear category for The End of Other by jusha
def checkio(words_set):
if len(words_set)==1:
return False
else:
lst = sorted(list(words_set), key = lambda i:len(i))
for i in range(len(lst)):
if any(y.endswith(lst[i]) for y in lst[i+1:]):
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print("Example:")
print(checkio({"hello", "lo", "he"}))
assert checkio({"hello", "lo", "he"}) == True, "helLO"
assert checkio({"hello", "la", "hellow", "cow"}) == False, "hellow la cow"
assert checkio({"walk", "duckwalk"}) == True, "duck to walk"
assert checkio({"one"}) == False, "Only One"
assert checkio({"helicopter", "li", "he"}) == False, "Only end"
print("Done! Time to check!")
April 9, 2020
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