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Permutations solution in Speedy category for The End of Other by Ch0bits
from itertools import permutations
checkio = lambda words_set: any([a.endswith(b) for a, b in permutations(words_set, 2)])
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio({"hello", "lo", "he"}) == True, "helLO"
assert checkio({"hello", "la", "hellow", "cow"}) == False, "hellow la cow"
assert checkio({"walk", "duckwalk"}) == True, "duck to walk"
assert checkio({"one"}) == False, "Only One"
assert checkio({"helicopter", "li", "he"}) == False, "Only end"
March 13, 2014
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