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First solution in Clear category for Double Substring by colinmcnicholl
import re
def double_substring(line):
"""
length of the longest substring that non-overlapping repeats more than once.
"""
matches = re.findall(r'(.+)(?=.*\1)', line)
largest = '' if not matches else max(matches, key=lambda m: len(m))
return len(largest)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert double_substring('aaaa') == 2, "First"
assert double_substring('abc') == 0, "Second"
assert double_substring('aghtfghkofgh') == 3, "Third"
print('"Run" is good. How is "Check"?')
Dec. 4, 2017
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