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Disposable Recursion solution in Clear category for Disposable Teleports by hrvoje
def checkio(teleports_string):
teleports, paths = {frozenset(i) for i in teleports_string.split(',')}, []
def walk(station, links, path):
if len(set(path)) == 8 and station == '1':
paths.append(path+station)
for link in filter(lambda x: station in x, links):
walk(next(iter(link-{station})), links-{link}, path+station)
walk('1', teleports, '')
return min(paths, key=len)
Aug. 16, 2015
