dsd clear solution for Digits Multiplication by weroniquue - python coding challenges

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dsd solution in Clear category for Digits Multiplication by weroniquue

def checkio(number):
    liczba= str(number)
    x = 1
    for i in liczba:
        if int(i) !=0:
            x = x * int(i)
    return x
        
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(123405) == 120
    assert checkio(999) == 729
    assert checkio(1000) == 1
    assert checkio(1111) == 1

Oct. 28, 2016

Comments:

suic on Nov. 1, 2016, 4:58 p.m.
<p>Hi, </p> <ol> <li>you can save an `int()` conversion</li> <li>you canremove the `liczba` variable</li> <li>other way of solving this mission is using `filter()` and `reduce()`</li> </ol> <p>I'm not saying that either of the below solution is better than yours :) My point is that this type of refactoring is useful for exploring Python :) ...</p> <p>Regards,</p> <p>suic</p> <p>```python</p> <h1>with map</h1> <p>def checkio(number): x = 1 for i in map(int, str(number)): if i != 0: x *= i return x</p> <h1>with map and filter</h1> <p>def checkio(number): x = 1 for i in filter(None, map(int, str(number))): x *= i return x</p> <h1>with map, filter and reduce</h1> <p>from functools import reduce from operator import mul</p> <p>def checkio(number): return reduce(mul, filter(None, map(int, str(number)))) ```</p>

Strings and Integers

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