shifting number digitally speedy solution for Digits Multiplication by apotokin - python coding challenges - Py.CheckiO

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shifting number digitally solution in Speedy category for Digits Multiplication by apotokin

def checkio(number):
    mul=1
    while number != 0:
        mul *= number % 10 or 1
        number = number // 10
    return mul

July 26, 2015

Strings and Integers

0

0 %

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