First clear solution for Digits Multiplication by Reloader - python coding challenges

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First solution in Clear category for Digits Multiplication by Reloader

def checkio(number):
    product = 1
    for y in [x for x in str(number).replace('0', '')]:
        product *= int(y)
    return product

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(123405) == 120
    assert checkio(999) == 729
    assert checkio(1000) == 1
    assert checkio(1111) == 1

Feb. 24, 2014

Comments:

Daniel_Pereira on April 29, 2014, 9:51 p.m.
In the line 3, why not for y in str(number).replace('0', ''): ?

Reloader on April 30, 2014, 1:05 p.m.
You're right, your expression is simpler.

hanpari on April 30, 2014, 2:07 p.m.
And what about: <pre class='brush: python'>for y in str(number): product *= int(y) if y != "0" else 1 </pre>

Reloader on April 30, 2014, 2:50 p.m.
Nice, too!

hanpari on April 30, 2014, 3:27 p.m.
Thank you. I learnt this trick recently so I didnt use it either :)

Strings and Integers

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