Recursive checkio clear solution for Digits Multiplication by ISORAKao - python coding challenges

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Recursive checkio solution in Clear category for Digits Multiplication by ISORAKao

def checkio(number: int) -> int:
    if number < 10: 
        return number
    
    quotient = number//10
    remainder = number%10
    if remainder == 0: 
        remainder = 1
        
    return checkio(quotient)*remainder


if __name__ == '__main__':
    print('Example:')
    print(checkio(123405))
    
    # These "asserts" using only for self-checking and not necessary for auto-testing
    assert checkio(123405) == 120
    assert checkio(999) == 729
    assert checkio(1000) == 1
    assert checkio(1111) == 1
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

Dec. 17, 2019

Comments:

zalikovka on Dec. 19, 2019, 5:28 p.m.
<p>Thank you for recursive solution. I will optimize mine. Quotient can be removed, just number// in return. Reminder = 1 can be changed with return checkio(quotient), 2 operations per iteration less</p>

Strings and Integers

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