First creative solution for Digits Multiplication by Amachua - python coding challenges

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First solution in Creative category for Digits Multiplication by Amachua

checkio = lambda n: eval("*".join(i for i in str(n) if i != '0'))

Feb. 21, 2014

Comments:

Arandomusername on Feb. 26, 2015, 1:51 p.m.
Nice creative use

zamu on April 28, 2015, 12:06 a.m.
This can be further simplified to: <pre class='brush: python'>checkio = lambda n: eval('*'.join(i for i in str(n) if i)) </pre>

Riddick on June 24, 2015, 8:58 a.m.
Perfect solution!

MhdTahawi on Sept. 15, 2015, 3:29 p.m.
I love it !

yun_zynb on Nov. 18, 2015, 2:15 p.m.
awesome! creative! good job!!!

R2R on May 29, 2017, 11:32 a.m.
Great!

Freiling on July 2, 2017, 9:13 p.m.
Very cool. Would it be more resource intensive to do it this way ("if i != 0"), or to just replace the zeros with "" from the product of join()?

kipermail on Sept. 2, 2023, 2:19 p.m.
Very cool.

Strings and Integers

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