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Simple solution in Clear category for Digits Doublets by Pouf
def checkio(numbers):
paths = [[numbers[0]]]
while True:
p = paths.pop(0)
for c in set(numbers)-set(p):
if sum(x!=y for x, y in zip(str(p[-1]), str(c))) == 1:
if c == numbers[-1]:
return p + [c]
paths.append(p + [c])
Oct. 4, 2015
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