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First solution in Clear category for Digit Stack by zcjsword
def digit_stack(commands):
stack, ret = [], 0
for c in commands:
if "PUSH" in c:
stack.append(int(c[5:]))
else:
ret += 0 if not stack else stack[-1]
if stack and c == "POP":
stack.pop()
return ret
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert digit_stack(["PUSH 3", "POP", "POP", "PUSH 4", "PEEK",
"PUSH 9", "PUSH 0", "PEEK", "POP", "PUSH 1", "PEEK"]) == 8, "Example"
assert digit_stack(["POP", "POP"]) == 0, "pop, pop, zero"
assert digit_stack(["PUSH 9", "PUSH 9", "POP"]) == 9, "Push the button"
assert digit_stack([]) == 0, "Nothing"
Dec. 10, 2015
