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First solution in Uncategorized category for Digit Stack by Mahoter
def digit_stack(commands):
stack = []
res = 0
for com in commands:
if com[0:4] == "PUSH":
stack += [int(com[5:6])]
if com[0:3] == "POP" and len(stack) > 0:
a = stack.pop()
res += a
if com[0:4] == "PEEK" and len(stack) > 0:
a = stack[len(stack)-1]
res += a
return res
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert digit_stack(["PUSH 3", "POP", "POP", "PUSH 4", "PEEK",
"PUSH 9", "PUSH 0", "PEEK", "POP", "PUSH 1", "PEEK"]) == 8, "Example"
assert digit_stack(["POP", "POP"]) == 0, "pop, pop, zero"
assert digit_stack(["PUSH 9", "PUSH 9", "POP"]) == 9, "Push the button"
assert digit_stack([]) == 0, "Nothing"
Jan. 17, 2016
