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Digit Stack solution in Clear category for Digit Stack by KacperBeisert
def digit_stack(commands):
stack = []
sum = 0
for command in commands:
if command == "POP":
sum += stack.pop() if stack else 0
if command == "PEEK":
sum += stack[-1] if stack else 0
if command.startswith("PUSH"):
stack.append(int(command.split(" ")[1]))
return sum
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert digit_stack(["PUSH 3", "POP", "POP", "PUSH 4", "PEEK",
"PUSH 9", "PUSH 0", "PEEK", "POP", "PUSH 1", "PEEK"]) == 8, "Example"
assert digit_stack(["POP", "POP"]) == 0, "pop, pop, zero"
assert digit_stack(["PUSH 9", "PUSH 9", "POP"]) == 9, "Push the button"
assert digit_stack([]) == 0, "Nothing"
Dec. 4, 2015
