Simple clear solution for Determine the Order by Sim0000 - python coding challenges

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Simple solution in Clear category for Determine the Order by Sim0000

def checkio(data):
    alphabet = sorted(set(''.join(data))) # unique alphabet
    result = ''
    for n in range(len(alphabet)):
        # find minimum
        for c in alphabet:
            if c in result: continue # already used
            if all(c not in word or c == word[0] for word in data): break # found
        result += c
        # remove c from data
        for i in range(len(data)): data[i] = data[i].replace(c, '')
    return result


#These "asserts" using only for self-checking and not necessary for auto-testing

May 5, 2014

Comments:

tarasenkoa on June 23, 2015, 12:54 p.m.
Great, really simple!

Thenbacker on Oct. 25, 2016, 12:24 a.m.
Great solution!

jakubbortlik on Dec. 16, 2022, 9:05 a.m.
Very nice solution! I find that using `data[i].lstrip(c)` instead of `data[i].replace(c, '')` on line 11 would help me understand right away that we are getting rig of the current "minimum". It's also slightly simpler (only one argument) and I imagine it can run faster by a couple of nanoseconds since it does not have to check the whole string. The last note is not to be taken too seriously. I am relatively new to Python and am still learning about ways how to do things efficiently, so I like to think about how different approaches to the same task compare on various levels :)

egkrivotuloff on April 8, 2023, 1:13 p.m.
Damn it's so easy to understand and so unclear to invent. Nice solution

List, list and list again

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