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First solution in Speedy category for Days Between by zator55
from datetime import date, timedelta
def days_diff(date1, date2):
f=date(*date1)
b=date(*date2)
a=(f-b).days
return abs(a)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
Dec. 12, 2015
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