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First solution in Clear category for Days Between by sanketchaudhari0608
from datetime import date, timedelta
def days_diff(a, b):
# your code here
d1, d2 = date(year=a[0], month=a[1], day=a[2]), date(year=b[0], month=b[1], day=b[2])
return abs((d1-d2).days)
if __name__ == '__main__':
print("Example:")
print(days_diff((1982, 4, 19), (1982, 4, 22)))
# These "asserts" are used for self-checking and not for an auto-testing
assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
print("Coding complete? Click 'Check' to earn cool rewards!")
April 6, 2020
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