Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Datetime.date, datetime.timedelta solution in Clear category for Days Between by ail531
from datetime import date, timedelta
def days_diff(a, b):
f_year, f_month, f_day = a
s_year, s_month, s_day = b
f = date(f_year, f_month, f_day)
s = date(s_year, s_month, s_day)
return abs((f - s).days)
if __name__ == '__main__':
print("Example:")
print(days_diff((1982, 4, 19), (1982, 4, 22)))
# These "asserts" are used for self-checking and not for an auto-testing
assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
print("Coding complete? Click 'Check' to earn cool rewards!")
June 9, 2020
