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First solution in Clear category for Days Between by PiotrStachowiak
def days_diff(d1, d2):
from datetime import date, timedelta
f=date(d1[0],d1[1],d1[2])
s=date(d2[0],d2[1],d2[2])
x=abs((f-s).days)
return timedelta(x).days
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
Nov. 27, 2016
