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Concise algorithm solution in Speedy category for Date and Time Converter by Igor_Sekretarev
from datetime import datetime
def date_time(time: str) -> str:
dt = datetime.strptime(time, '%d.%m.%Y %H:%M')
hour_word = 'hour' if dt.hour == 1 else 'hours'
minute_word = 'minute' if dt.minute == 1 else 'minutes'
return dt.strftime(f'%-d %B %Y year %-H {hour_word} %-M {minute_word}')
if __name__ == '__main__':
print("Example:")
print(date_time('01.01.2000 00:00'))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert date_time("01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes", "Millenium"
assert date_time("09.05.1945 06:30") == "9 May 1945 year 6 hours 30 minutes", "Victory"
assert date_time("20.11.1990 03:55") == "20 November 1990 year 3 hours 55 minutes", "Somebody was born"
print("Coding complete? Click 'Check' to earn cool rewards!")
April 24, 2021
