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First solution in Clear category for Counting Tiles by klaganowski
from math import ceil
def checkio(radius):
solid, partial = 0, 0
top = radius
bottom = radius
for i in range(1, int(radius)+1):
bottom = (radius**2-i**2)**.5
solid += int(bottom)
partial += int(ceil(top))-int(bottom)
top = bottom
if int(radius) != radius:
partial += int(ceil(bottom))
return [4*solid, 4*partial]
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(2) == [4, 12], "N=2"
assert checkio(3) == [16, 20], "N=3"
assert checkio(2.1) == [4, 20], "N=2.1"
assert checkio(2.5) == [12, 20], "N=2.5"
Dec. 5, 2016
