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First solution in Clear category for Moore Neighbourhood by baozhao123
def count_neighbours(grid, row, col):
n = len(grid)
m = len(grid[0])
dx = (1, 1, 1, 0, 0, -1, -1, -1)
dy = (1, 0, -1, 1, -1, 1, 0, -1)
ans = 0
for i in range(8):
nx = row + dx[i]
ny = col + dy[i]
if nx >= 0 and nx < n and ny >= 0 and ny < m:
ans += grid[nx][ny]
return ans
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(
((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
Oct. 18, 2014