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Solution with checking the border of the list solution in Clear category for Moore Neighbourhood by Mr.Geekman
def count_neighbours(grid, row, col):
count = 0
for yi in range(row - 1, row + 2):
for xi in range(col - 1, col + 2):
if xi >= 0 and xi <= len(grid[0]) - 1 and yi >= 0 and\
yi <= len(grid) - 1 and (xi != col or yi != row):
count += grid[yi][xi]
return count
return 0
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
April 14, 2016
