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Moore Neighbourhood solution in Uncategorized category for Moore Neighbourhood by KacperBeisert
def count_neighbours(grid, row, col):
count = 0
for x, y in (
(row - 1, col - 1), (row - 1, col), (row - 1, col + 1),
(row, col - 1), (row, col + 1),
(row + 1, col - 1), (row + 1, col), (row + 1, col + 1)):
if not (0 <= x < len(grid) and 0 <= y < len(grid[x])):
continue
if grid[x][y] == 1:
count = count + 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
Dec. 2, 2015
