Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Count Inversions by Mooshu
def count_inversion(sequence):
count = 0
array = list(sequence)
for i in range(0, len(array)):
for j in range(0, len(array)):
if i > j:
if array[i] < array[j]:
count += 1
else:
count = count
else:
count = count
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_inversion((1, 2, 5, 3, 4, 7, 6)) == 3, "Example"
assert count_inversion((0, 1, 2, 3)) == 0, "Sorted"
assert count_inversion((99, -99)) == 1, "Two numbers"
assert count_inversion((5, 3, 2, 1, 0)) == 10, "Reversed"
Oct. 18, 2015
Comments:
