Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Uncategorized category for Count Inversions by KWisniewski
def count_inversion(sequence):
c=0
for x in range(len(sequence)):
for j in range(x+1,len(sequence)):
if sequence[x]>sequence[j]:
c+=1
return c
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_inversion((1, 2, 5, 3, 4, 7, 6)) == 3, "Example"
assert count_inversion((0, 1, 2, 3)) == 0, "Sorted"
assert count_inversion((99, -99)) == 1, "Two numbers"
assert count_inversion((5, 3, 2, 1, 0)) == 10, "Reversed"
Dec. 20, 2015