First clear solution for Correct Sentence by Tinus_Trotyl - python coding challenges

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First solution in Clear category for Correct Sentence by Tinus_Trotyl

def correct_sentence(text: str) -> str:   
    return text[0].upper() + text[1:] + ("." if text[-1] != "." else "")

Nov. 11, 2017

Comments:

ChengJar on March 27, 2018, 7:36 a.m.
nice

Oguangpan on March 30, 2018, 2:25 p.m.
beautiful

joshua.m.hublar on May 2, 2018, 6:01 p.m.
gorgeous.

flyhigher365 on May 16, 2018, 2:56 a.m.
Very nice

IvanAndrukh on May 20, 2018, 8:34 p.m.
def correct_sentence(text): return (text.strip(".").capitalize()+".")

ElliotG on May 22, 2018, 1:50 a.m.
Will this work? Capitalized will capitalized the first letter, and lowercase all others.

MRZ1 on Dec. 26, 2018, 11:11 a.m.
may be this will work\ ```def correct_sentence(text): return (text[0].upper()+text[1:].strip(".")+".")```

DragonMachinations on Aug. 7, 2019, 6:06 p.m.
This is great.

Wombat164 on Dec. 14, 2021, 2:29 p.m.
Had the same, but with rstrip() :)

DookieShoes on May 21, 2018, 10:03 p.m.
What does adding ": str" and "-> str" do to the code? it seems to work without them.

ElliotG on May 22, 2018, 1:49 a.m.
They are called function annotations. They do not have a functional role. The describe the expected data types being passed to and returned from a function. <a href="https://docs.python.org/3/tutorial/controlflow.html">https://docs.python.org/3/tutorial/controlflow.html</a>#function-annotations

yyc1990 on May 28, 2018, 2:45 p.m.
good

m1n1stry on June 19, 2018, 4:30 p.m.
Nice!! Simple is better than complex.

xiaoTian on July 10, 2018, 3:45 a.m.
nice

logan4070 on July 13, 2018, 1:44 a.m.
cool

Juanpalx on Aug. 4, 2018, 3:21 p.m.
The last term ("." if text[-1] != "." else "") is clean and clear. However I would like to suggest another option "."*(text[-1] != ".")

lukewarm92 on Sept. 30, 2018, 4:49 p.m.
Damn it's good!

Turo233 on Oct. 19, 2018, 6:17 a.m.
cool!

citizen65535 on Jan. 6, 2019, 8:57 p.m.
Is parentheses here just for most clear view? Is this still correct: return text[0].upper() + text[1:] + "." if text[-1] != "." else ""

citizen65535 on Jan. 6, 2019, 8:59 p.m.
Oh, I checked, will not work correctly

jorgesenpai on Nov. 8, 2022, 6:45 p.m.
how python determine what to do when «if» is true? i.e.: (text[1:]+".") or to do only (".")?

MSL on Jan. 31, 2019, 9:40 a.m.
python is so beautiful! nice solution!

briantruong on Feb. 23, 2019, 9:58 p.m.
woa !!!

pruidzeko on April 29, 2019, 6:27 a.m.
I stopped using single-line solutions, because they are not readable. But perhaps this only makes sense in terms of increasing the speed of calculations. It will be necessary to check this aspect.

big_h_chicken on July 22, 2019, 5:29 p.m.
big brain

anplaceb on Aug. 9, 2019, 10:41 a.m.
Good solution!

Steven2222 on Sept. 3, 2019, 8:13 a.m.
Nice.

LarceFox on Sept. 25, 2019, 10:35 a.m.
In my answer I writed the same, but I do'n think that it is the best solution. Because every time you use '+' with string array Python makes another copy of string object and use more system memory then in other solutions.

jorgesenpai on Nov. 8, 2022, 6:49 p.m.
In your opinion: what is the fastest way? «append» is fastest or slower than «+»?

bk92 on Sept. 1, 2020, 10:12 p.m.
very concise!

sungi9700 on Jan. 8, 2021, 1:49 a.m.
could you explane what ! works?

Tinus_Trotyl on Jan. 9, 2021, 6:52 p.m.
'!=' stands for: 'is not equal'

olgag on Feb. 5, 2021, 10:18 p.m.
the last one also can be changed by using a standard function like this ("." if not text.endswith('.') else "")

bkaraica on March 15, 2021, 7:35 p.m.
The last part is a nice way to make and if else for a ".". I did it slightly differently which resulted in a longer line. Bravo

CIOHarazi on April 26, 2021, 8:52 a.m.
Did what I did but got it all on one line. Nice job

alekssamos on Sept. 16, 2021, 2:33 p.m.
Good, but it is difficult to perceive in one line

Bangstardo on Oct. 21, 2021, 7:46 p.m.
would text.replace("word","Word")+("." if text[-1] != "." else "") be viable

jorgesenpai on Nov. 8, 2022, 6:54 p.m.
only works if first word is exactly «word», i mean, i.e. don't works in: «wOrd word2.»,«a word»«one two.»...

phongtt2 on April 20, 2022, 10:28 a.m.
nice

tookello on Sept. 6, 2022, 11:26 a.m.
It is really clear

kdim on Sept. 8, 2022, 6:04 p.m.
Nice and clear solution.

2502019108 on Oct. 20, 2022, 6:06 a.m.
Damn!!!awesome

Bodeq on Oct. 22, 2022, 1:41 p.m.
fine

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