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First: collections.defaultdict solution in Creative category for Convert and Aggregate by hbczmxy
from collections import defaultdict
def conv_aggr(data: list[tuple[str, int]]) -> dict[str, int]:
# your code here
result = defaultdict(int)
for key, value in data:
if key != "":
result[key] += value
else:
result = {key: value for key, value in result.items() if value != 0}
return result
print("Example:")
print(conv_aggr([("a", 7), ("b", 8), ("a", 10)]))
# These "asserts" are used for self-checking
assert conv_aggr([("a", 7), ("b", 8), ("a", 10)]) == {"a": 17, "b": 8}
assert conv_aggr([]) == {}
assert conv_aggr([("a", 5), ("a", -5)]) == {}
assert conv_aggr([("a", 5), ("a", 5), ("a", 0)]) == {"a": 10}
assert conv_aggr([("a", 5), ("", 15)]) == {"a": 5}
print("The mission is done! Click 'Check Solution' to earn rewards!")
Jan. 16, 2023
