Without if/else creative solution for Compare Functions by martin_b - python coding challenges

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Without if/else solution in Creative category for Compare Functions by martin_b

def checkio(f, g):
    def c(f, *args, **kwargs):
        try:
            return f(*args, **kwargs)
        except:
            return None

    def h(*args, **kwargs):
        fr = c(f, *args, **kwargs)
        gr = c(g, *args, **kwargs)
        return {
            (False, False): (None, 'both_error'),
            (True, False): (fr, 'g_error'),
            (False, True): (gr, 'f_error'),
            (True, True): (fr, {True: 'same', False: 'different'}[fr == gr])
        }[(fr != None, gr != None)]
    return h

April 1, 2016

Comments:

ljy95135 on April 19, 2016, 7:14 a.m.
Use a dict by tuple of True and False as a key is quite interesting. Learn it now.

hanpari on Jan. 26, 2017, 8:17 p.m.
I like your solution except for one thing. You are way too talkative <pre class='brush: python'>fr = c(f, *args, **kwargs) gr = c(g, *args, **kwargs) </pre> actually, <pre class='brush: python'>fr, gr = map(lambda h: c(h, *args, **kwargs), (f,g)) </pre> will make you noble and silent man. PS: Just kidding :) Nice one.

veky on Nov. 7, 2017, 3:12 p.m.
<pre class='brush: python'>{True: 'same', False: 'different'} ~~~> 'different same'.split() </pre>

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