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Simple and sparse solution in Clear category for Common Words by Splitter
def checkio(first, second):
transform = lambda x: set(x.split(','))
common = transform(first)
common &= transform(second)
return ','.join(sorted(list(common)))
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("hello,world", "hello,earth") == "hello", "Hello"
assert checkio("one,two,three", "four,five,six") == "", "Too different"
assert checkio("one,two,three", "four,five,one,two,six,three") == "one,three,two", "1 2 3"
March 12, 2020
