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First solution in Clear category for Common Words by Kurush
# migrated from python 2.7
def checkio(first, second):
common_words = set()
for word in first.split(","):
for word2 in second.split(","):
if word == word2:
common_words.add(word)
return ",".join(sorted(common_words))
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("hello,world", "hello,earth") == "hello", "Hello"
assert checkio("one,two,three", "four,five,six") == "", "Too different"
assert checkio("one,two,three", "four,five,one,two,six,three") == "one,three,two", "1 2 3"
June 8, 2014
