injectivity creative solution for Cipher Crossword by veky - python coding challenges

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injectivity solution in Creative category for Cipher Crossword by veky

def checkio(x,W):
 for w in __import__("itertools").permutations(W):
  p=set(sum((list(zip(*z))for z in zip(x[::2]+list(zip(*x))[::2],w)),[]))
  if len(p)==len(dict(p)):return[[dict(p).get(l,' ')for l in r]for r in x]

Feb. 22, 2014

Comments:

hrvoje on July 13, 2015, 12:40 a.m.
Ok, this is seriously, seriously awesome and clever! 5 thumbs falls short.

U.V on Jan. 25, 2023, 2:30 p.m.
It's new for me this original using of _ import _ . I put this trick in my collection !

veky on Jan. 25, 2023, 3:15 p.m.
that is just trading horizontal space for vertical one. There are much more cool things in the above solution. 😉

List, list and list again

0 %

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