4-liner: Done using chain & zip speedy solution for Chunk by Stensen - python coding challenges

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4-liner: Done using chain & zip solution in Speedy category for Chunk by Stensen

from itertools import chain
def chunking_by(items, step):
    temp = zip(chain([0], range(0, len(items), step)), chain(range(0, len(items), step), [None])) 
    return list(items[i:j] for i, j in temp if items[i:j])

Oct. 24, 2020

Comments:

mmartsinenko on Dec. 7, 2024, 11:15 p.m.
<p>This solution uses itertools.chain and zip to dynamically pair indices for slicing, an advanced technique for constructing chunks. It gracefully handles edge cases like an empty list by ensuring slicing operations are only performed when valid. This approach stands out for its creative use of built-in tools, although it may add some overhead due to intermediate iterable creation.</p>

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