125 creative solution for Call to Home by StefanPochmann - python coding challenges

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125 solution in Creative category for Call to Home by StefanPochmann

def total_cost(C):
 t=p=m=0
 for c in C+('',):
    if c[:10]!=p:t+=m+max(0,m-100);m=0;p=c[:10]
    m-=-int('0'+c[20:])/60
 return t

April 29, 2015

Comments:

StefanPochmann on April 29, 2015, 6:22 p.m.
125 is the file size in bytes. It's 127 with double spaces instead of tabs. Here's another 127: <pre class='brush: python'>def total_cost(C): M={} for c in C:M[c[:10]]=M.get(c[:10],0)-(-int(c[20:])/60) return sum(m+max(0,m-100)for m in M.values()) </pre>

veky on April 29, 2015, 8:50 p.m.
Are you sure you need () for -(-)?

StefanPochmann on April 29, 2015, 8:57 p.m.
Aw ** how did I not see that. Right after we talked about that. Oh well, at least it's not sub-125.

veky on April 29, 2015, 9:08 p.m.
This is good, it shows you're human and therefore beatable. :-D [-100 is one char shorter as ~99, but m-100 is same len as ~99+m. :-/]

DiZ on April 29, 2015, 9:27 p.m.
2 chars less with (4 chars included () and 5 if you use Python 2 integer division /): <pre class='brush: python'>def total_cost(C): M={} for c in C:M[c[:10]]=M.get(c[:10],0)--int(c[20:])//60 return sum(M[m]+max(0,M[m]-100)for m in M) </pre>

StefanPochmann on April 29, 2015, 10:40 p.m.
Sweet :-). Funny how I thought something like "DiZ just needs to get rid of those long library words" and then I overlooked one myself. Shaving off one more, don't know why I didn't try that before: 121: <pre class='brush: python'>def total_cost(C): M={} for c in C:d=c[:10];M[d]=M.get(d,0)--int(c[20:])/60 return sum(M[m]+max(0,M[m]-100)for m in M) </pre>

daustoe on Aug. 14, 2017, 11:10 p.m.
Whoa

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