Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Solutions for "Brackets" solution in Clear category for Brackets by zywang
def checkio(expression):
l=[i if i in '(){}[]' else '' for i in expression]
s=''.join(l)
while '()' in s or '[]' in s or '{}' in s:
s=s.replace('()', '')
s=s.replace('[]', '')
s=s.replace('{}', '')
return s==''
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Oct. 13, 2020
Comments:
