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First solution in Clear category for Brackets by wojtek96
d = {"{": "}", "[": "]", "(": ")"}
def checkio(expression):
list = []
for i in expression:
if i in d.keys():
list.append(i)
if i in d.values():
if not (list and d[list.pop()] == i):
return False
return not list
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Dec. 15, 2016
