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First solution in Clear category for Brackets by wbl4126
def checkio(expression):
d = {']':'[', ')':'(', '}':'{'}
tmp = []
for s in expression:
if s in '[({':
tmp += s
elif s in '])}' and (not tmp or tmp and tmp.pop() != d[s]):
return False
return not tmp
April 10, 2020
