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Second solution in Uncategorized category for Brackets by vvm70
def checkio(expr):
brackets = ''.join(s for s in expr if s in "()[]{}")
while "[]" in brackets or "{}" in brackets or "()" in brackets:
brackets = brackets.replace("()", '').replace("[]", '').replace("{}", '')
return not brackets
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Nov. 2, 2020
