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Stack solution in Clear category for Brackets by veky
def checkio(data):
stack=[""]
brackets={"(":")","[":"]","{":"}"}
for c in data:
if c in brackets:
stack.append(brackets[c])
elif c in brackets.values() and c!=stack.pop():
return False
return stack==[""]
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
May 29, 2013
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