Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Uncategorized category for Brackets by slygoblin
def checkio(expression):
brackets = []
for e in expression:
if e == "(":
brackets.append(")")
if e == "[":
brackets.append("]")
if e == "{":
brackets.append("}")
if e == ")" or e == "]" or e == "}":
if not brackets or e != brackets.pop():
return False
if len(brackets)==0:
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Dec. 11, 2015