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pushing and poping solution in Clear category for Brackets by sjosef23
def checkio(expression):
symbols = {'(':')', '[':']', '{':'}'}
l = []
for c in expression:
if c in symbols.keys():
l.append(symbols[c])
elif c in symbols.values():
if not l:
return False
if l.pop() != c:
return False
if l:
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
May 9, 2020
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