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4 ifs in a loop solution in Clear category for Brackets by odwl
def checkio(expr):
state = []
for char in expr:
if char in ('(', '[', '{') :
state.append(char)
if char == ')':
if not state or state[-1] != "(": return False
state.pop()
if char == ']':
if not state or state[-1] != "[": return False
state.pop()
if char == '}':
if not state or state[-1] != "{": return False
state.pop()
return not state
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
March 2, 2014
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