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First solution in Clear category for Brackets by lukasz.bogaczynski
brackets = {
"{": "}",
"[": "]",
"(": ")"
}
def checkio(expression):
opened_brackets = []
for char in expression:
if char in brackets.keys():
opened_brackets.append(char)
continue
elif char in brackets.values():
if len(opened_brackets) < 1:
return False
if brackets[opened_brackets[len(opened_brackets) - 1]] == char:
opened_brackets.pop()
continue
else:
return False
if len(opened_brackets) > 0:
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Oct. 25, 2017
