Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Brackets by lisovsky
def checkio(expression: str) -> bool:
lst = []
for c in expression:
if c == "{":
lst.append("}")
elif c == "(":
lst.append(")")
elif c == "[":
lst.append("]")
elif c in ("}", ")", "]"):
if len(lst) == 0 or lst.pop() != c:
return False
return len(lst) == 0
# These "asserts" using only for self-checking and not necessary for auto-testing
print("Example:")
print(checkio("((5+3)*2+1)"))
assert checkio("((5+3)*2+1)") == True
assert checkio("{[(3+1)+2]+}") == True
assert checkio("(3+{1-1)}") == False
assert checkio("[1+1]+(2*2)-{3/3}") == True
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False
assert checkio("[(3)+(-1)]*{3}") == True
assert checkio("(((([[[{{{3}}}]]]]))))") == False
assert checkio("[1+202]*3*({4+3)}") == False
assert checkio("({[3]})-[4/(3*{1001-1000}*3)/4]") == True
assert checkio("[[[1+[1+1]]])") == False
assert checkio("(((1+(1+1))))]") == False
assert checkio("2+3") == True
print("The mission is done! Click 'Check Solution' to earn rewards!")
Sept. 18, 2022
