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First solution in Clear category for Brackets by f_rin_kazan
def checkio(expr):
for c in '1234567890+-*/':
expr = expr.replace(c, '')
length = len(expr)
while length:
if expr.count('()'):
expr = expr.replace('()','')
if expr.count('{}'):
expr = expr.replace('{}','')
if expr.count('[]'):
expr = expr.replace('[]','')
if len(expr) == length:
break
else:
length = len(expr)
return len(expr) == 0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
Feb. 26, 2014
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